. The lines `(a+b)x + (a-b) y-2ab=0, (a-b)x+(a+b)y-2ab = 0 and x+y=0` form an isosceles triangle whose vertical angle is
(1) `pi/2`
(2) `tan^-1 ((2ab)/(a^2-b^2))`
(3) `tan^-1 (a/b)`
(4) `2 tan^-1 (a/b)`
Topper's Solved these Questions
STRAIGHT LINE
FIITJEE|Exercise Exercise 5|4 Videos
STRAIGHT LINE
FIITJEE|Exercise Exercise 6|4 Videos
STRAIGHT LINE
FIITJEE|Exercise Exercise 3|5 Videos
STATISTICS
FIITJEE|Exercise Comprehension Type|6 Videos
TEST PAPERS
FIITJEE|Exercise MATHEMATICS|328 Videos
Similar Questions
Explore conceptually related problems
y = tan ^ (- 1) [sqrt ((ab) / (a + b)) (tan x) / (2)]
(a-b)x+(a+b)y=a^(2)-2ab-b^(2)(a+b)(x+y)=a^(2)+b^(2) find x and y
If A (-3, 2) , B(x, y) and C(1, 4) are the vertices of an isosceles triangle with AB=BC . Find the value of (2x+y) .
tan [tan ^ (- 1) ((1) / (a + b)) + tan ^ (- 1) ((b) / (a ^ (2) + ab + 1))] =
Two sides of a triangle are (a+b)x+(a-b)y-2ab=0 and (a-b)x+(a+b)y-2ab=0 .If the triangle is isosceles and the third side passes through point (b-a,a-b), then the equation of third side can be
The area of the triangle OAB with vertices O(0,0),A(x_(1),y_(1))" and B(x_(2),y_(2)) is
In a triangle ABC if tan.(A)/(2)tan.(B)/(2)=(1)/(3) and ab = 4, then the value of c can be