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The vertices Ba n dC of a triangle A B C...

The vertices `Ba n dC` of a triangle `A B C` lie on the lines `3y=4xa n dy=0` , respectively, and the side `B C` passes through the point `(2/3,2/3)` . If `A B O C` is a rhombus lying in the first quadrant, `O` being the origin, find the equation of the line `B Cdot`

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The correct Answer is:
`2x+y-2=0,(8/5,4/5)`
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