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The straight line x/a+y/b=1 cuts the axe...

The straight line `x/a+y/b=1` cuts the axes in A and B and a line perpendicular to AB cuts the axes in P and Q. Find the locus of the point of intersection of AQ and BP .

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The correct Answer is:
`x^2+y^2-ax - by = 0 `
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