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A (-3,4) , B (5,4) , C and D form a rect...

A (-3,4) , B (5,4) , C and D form a rectangle `X - 4y+7=0` is a diameter of the circumcirle of the rectangle ABCD, the area of `DeltaABC` is

A

8

B

16

C

32

D

64

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To solve the problem, we need to find the area of triangle ABC formed by points A, B, and C, given that A(-3, 4) and B(5, 4) are two vertices of a rectangle ABCD, and the line \(X - 4y + 7 = 0\) is the diameter of the circumcircle of the rectangle. ### Step-by-Step Solution: 1. **Identify Points A and B**: - Point A is given as (-3, 4). - Point B is given as (5, 4). 2. **Determine the Midpoint of AB**: - The midpoint \(E\) of segment \(AB\) can be calculated using the midpoint formula: \[ E = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right) = \left(\frac{-3 + 5}{2}, \frac{4 + 4}{2}\right) = \left(1, 4\right) \] 3. **Find the Equation of the Perpendicular Bisector of AB**: - Since AB is horizontal (y = 4), the perpendicular bisector will be a vertical line passing through E. - Therefore, the equation of the perpendicular bisector is \(x = 1\). 4. **Find the Intersection of the Perpendicular Bisector with the Diameter**: - The diameter of the circumcircle is given by the line equation \(x - 4y + 7 = 0\). - Substitute \(x = 1\) into the line equation: \[ 1 - 4y + 7 = 0 \implies 4y = 8 \implies y = 2 \] - Thus, the center of the circumcircle (and also the midpoint of the rectangle) is at point \(C(1, 2)\). 5. **Identify the Coordinates of Point D**: - Since the rectangle is symmetric about the midpoint, point D will have the same x-coordinate as point C and the same y-coordinate as point A. - Thus, point D will be at \(D(1, 4)\). 6. **Calculate the Area of Triangle ABC**: - The area of triangle ABC can be calculated using the formula: \[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \] - Here, the base \(AB\) is the distance between points A and B: \[ AB = |x_2 - x_1| = |5 - (-3)| = 8 \] - The height is the vertical distance from point C to line AB (which is at y = 4): \[ \text{Height} = |y_C - y_{AB}| = |2 - 4| = 2 \] - Now, substituting these values into the area formula: \[ \text{Area} = \frac{1}{2} \times 8 \times 2 = 8 \] ### Final Answer: The area of triangle ABC is \(8\).
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