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Prove that the area of the parallelogram...

Prove that the area of the parallelogram formed by the lines `xcosalpha+ysinalpha=p ,xcosalpha+ys inalpha=q ,xcosbeta+ysinbeta=ra n dx cosbeta+ysinbeta=si s+-(p-q)(r-s)cos e c(alpha-beta)dot`

A

`pq+rs`

B

`|pq tan alpha + rs tan beta|`

C

`|(p-q) (r - s ) cosec (alpha - beta)|`

D

`|(p - q ) (r - s ) tan (alpha + beta)|`

Text Solution

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The correct Answer is:
C
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