Home
Class 12
MATHS
In an isosceles right angled triangle , ...

In an isosceles right angled triangle , a straight line drwan from the mid - point of one of equal sides to the opposite angle . It divides the angle into two parts , `theta and (pi//4-theta)` . Then `tan theta and tan [(pi//4) -theta]` are equal to

A

`1/2,1/3`

B

`1/3,1/4`

C

`1/5,1/6`

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the values of \( \tan \theta \) and \( \tan \left( \frac{\pi}{4} - \theta \right) \) in the context of an isosceles right triangle where a line is drawn from the midpoint of one of the equal sides to the opposite angle. ### Step-by-Step Solution: 1. **Define the Triangle**: Let's denote the isosceles right triangle as \( \triangle ABC \) where \( AB = AC = 2x \) and \( \angle A = 90^\circ \). The midpoint of side \( AB \) is point \( G \). 2. **Draw the Line**: Draw a line from point \( G \) to point \( C \). This line divides \( \angle A \) into two angles: \( \theta \) and \( \frac{\pi}{4} - \theta \). 3. **Identify Triangle \( \triangle ABG \)**: In triangle \( ABG \): - The length \( AG = x \) (since \( G \) is the midpoint of \( AB \)). - The length \( BG = x \) (since \( G \) is the midpoint of \( AB \)). - The length \( AB = 2x \). 4. **Calculate \( \tan \theta \)**: Using the definition of tangent in triangle \( ABG \): \[ \tan \theta = \frac{\text{opposite}}{\text{adjacent}} = \frac{AG}{BG} = \frac{x}{x} = 1 \] However, we need to find the relationship involving \( 2x \) and \( x \): \[ \tan \theta = \frac{2x}{x} = 2 \quad \text{(using the full length of the side)} \] 5. **Calculate \( \tan \left( \frac{\pi}{4} - \theta \right) \)**: We use the identity: \[ \tan \left( \frac{\pi}{4} - \theta \right) = \frac{1 - \tan \theta}{1 + \tan \theta} \] Substituting \( \tan \theta = 2 \): \[ \tan \left( \frac{\pi}{4} - \theta \right) = \frac{1 - 2}{1 + 2} = \frac{-1}{3} = -\frac{1}{3} \] 6. **Final Values**: Thus, we have: \[ \tan \theta = 2 \quad \text{and} \quad \tan \left( \frac{\pi}{4} - \theta \right) = -\frac{1}{3} \] ### Conclusion: The values of \( \tan \theta \) and \( \tan \left( \frac{\pi}{4} - \theta \right) \) are \( 2 \) and \( -\frac{1}{3} \) respectively.
Promotional Banner

Topper's Solved these Questions

  • STRAIGHT LINE

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (OBJECTIVE) Level - II|20 Videos
  • STRAIGHT LINE

    FIITJEE|Exercise COMPREHENSIONS|9 Videos
  • STRAIGHT LINE

    FIITJEE|Exercise ASSIGNMENT PROBLEMS (SUBJECTIVE) Level - II|14 Videos
  • STATISTICS

    FIITJEE|Exercise Comprehension Type|6 Videos
  • TEST PAPERS

    FIITJEE|Exercise MATHEMATICS|328 Videos

Similar Questions

Explore conceptually related problems

tan(pi/4+theta)+tan(pi/4-theta)=4

tan ((pi)/(4)+theta) tan ((3pi)/( 4) + theta) is equal to

Prove that tan(pi/4+theta/2)=sec theta+tan theta

If tan theta=-(4)/(3) then sin theta is equal to

ABC is right angled triangle, right angled at C . D is the midpoint of BC. Then , (tan theta)/( tan phi) =

tan ((pi)/(4) + (theta)/(2)) + tan ((pi)/(4) -(theta)/(2)) is equal to

If tan theta + tan (pi/3 +theta) + tan (frac{2pi}{3}+ theta) = k tan 3theta then k is equal to

If tan theta+tan4 theta+tan7 theta=tan theta tan4 theta tan7 theta, then theta is equal to

FIITJEE-STRAIGHT LINE -ASSIGNMENT PROBLEMS (OBJECTIVE) Level - I
  1. Consider the equation y - y(1) = m(x - x(1)). If m and different lines...

    Text Solution

    |

  2. The medians A D\ a n d\ B E of a triangle with vertices A(0, b),\ B(0,...

    Text Solution

    |

  3. If DeltaOAB is an equilateral triangle (O is the origin and A is a poi...

    Text Solution

    |

  4. Let 2x - 3y = 0 be a given line and P (sintheta, 0) and Q(0, costheta)...

    Text Solution

    |

  5. The sides of a rhombus ABCD are parallel to the lines x−y+2=0 and 7x−y...

    Text Solution

    |

  6. If the lines ax+12y+1=0 bx+13y+1=0 and cx+14y+1=0 are concurrent then ...

    Text Solution

    |

  7. The equations of the lines through (-1,-1) and making anlge 45^@ with ...

    Text Solution

    |

  8. The equation to a pair of opposite sides of a parallelogram are x^2-5x...

    Text Solution

    |

  9. The locus of a point P which divides the line joining (1,0) and (2 cos...

    Text Solution

    |

  10. In an isosceles right angled triangle , a straight line drwan from the...

    Text Solution

    |

  11. A curve with equation of the form y=a x^4+b x^3+c x+d has zero gradien...

    Text Solution

    |

  12. The algebraic sum of the perpendicular distance from A(x1,y1),B(x2,y2)...

    Text Solution

    |

  13. If P = (1/xp,p),Q=(1/xq,q),R=(1/xr,r) where xkne0,k =p,q , r ne N , d...

    Text Solution

    |

  14. The line (p+2q)x+(p-3q)y=p-q for different values of p and q passes th...

    Text Solution

    |

  15. The lines 2x + y -1=0, ax+ 3y-3=0 and 3x + 2y -2=0 are concurrent for ...

    Text Solution

    |

  16. The difference of the tangents of the angles which the lines x^(2)(sec...

    Text Solution

    |

  17. If the line y=mx meets the lines x+2y-1=0 and 2x-y+3=0 at the same poi...

    Text Solution

    |

  18. If the line y l=sqrt(3)x cuts the curve x^2=y^2+3x y+5x^2+3y^2+4x+5y-1...

    Text Solution

    |

  19. Statement-1: The quadrilaterial whoe vertices (in order) are A(1,0), B...

    Text Solution

    |

  20. Statement 1 : Equation of the pair of lines bisecting the angle betwee...

    Text Solution

    |