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Let ABC be a triangle with equations of ...

Let ABC be a triangle with equations of the sides `AB, BC and CA` respectively `x - 2 = 0,y- 5 = 0 and 5x + 2y - 10 = 0.` Then the orthocentre of the triangle lies on the line

A

x - y = 0

B

3x - y = 1

C

4x + y = 13

D

x - 2y = 1

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The correct Answer is:
B,C
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