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The equation to the hyperbola of given t...

The equation to the hyperbola of given transverse axis 2a along x- axis and whoe vertex bisects the distance between the centre and the focus is

A

`x^(2)/a^(2) - y^(2)/(2a^(2) )= 1`

B

`x^(2)/a^(2) - y^(2)/(3a^(2)) = 1`

C

`x^(2)/a^(2) - y^(2)/(4a^(2)) = 1`

D

`x^(2)/a^(2) - y^(2)/(a^(2)//4) = 1`

Text Solution

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The correct Answer is:
B
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Knowledge Check

  • For hyperbola, If transverse axis = conjugate axis , then e =

    A
    0
    B
    1
    C
    2
    D
    `sqrt(2)`

  • The transverse axis of a hyperbola is along the x-axis and its length is 2a. The vertex of the hyperbola bisects the line segment joining the centre and the focus. The equation of the hyperbola is

    A
    `6x^(2)-y^(2)=3a^(2)`
    B
    `x^(2)-3y^(2)=3a^(2)`
    C
    `x^(2)-6y^(2)=3a^(2)`
    D
    `3x^(2)-y^(2)=3a^(2)`

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