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The solution of the differential equatio...

The solution of the differential equation `((dy)/(dx))^(2)-x((dy)/(dx))+y=0` is

A

`y=2`

B

`y=2x`

C

`y=2x-4`

D

`y=2x^(2)-4`

Text Solution

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The correct Answer is:
To solve the differential equation \[ \left(\frac{dy}{dx}\right)^2 - x\left(\frac{dy}{dx}\right) + y = 0, \] we can follow these steps: ### Step 1: Introduce a substitution Let \( p = \frac{dy}{dx} \). Then, we can rewrite the equation as: \[ p^2 - xp + y = 0. \] ### Step 2: Solve for \( y \) This is a quadratic equation in terms of \( p \). We can use the quadratic formula to solve for \( p \): \[ p = \frac{x \pm \sqrt{x^2 - 4y}}{2}. \] ### Step 3: Express \( y \) in terms of \( p \) Rearranging the equation gives us: \[ y = \frac{p^2 - xp}{1}. \] ### Step 4: Differentiate \( y \) with respect to \( x \) Now we differentiate \( y \) with respect to \( x \): \[ \frac{dy}{dx} = p = \frac{d}{dx}\left(\frac{p^2 - xp}{1}\right). \] ### Step 5: Substitute back the expression for \( p \) From our earlier expression, we can substitute \( p \) back into the equation. This will yield: \[ p = \frac{x \pm \sqrt{x^2 - 4y}}{2}. \] ### Step 6: Find the general solution To find the general solution, we can express \( y \) in terms of \( p \): \[ y = xp - p^2. \] ### Step 7: Identify the constant Since \( p \) is a constant, we can write: \[ y = xc - c^2, \] where \( c \) is a constant. ### Step 8: Final form of the solution Thus, the solution of the differential equation is: \[ y = xc - c^2, \] where \( c \) is an arbitrary constant.
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FIITJEE-TIPS-ASSIGNMENT (SECTION (I): MCQ (SINGLE CORRECT)
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