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Let g(x)=e^f(x)), g(x+1)=xg(x), then (g'...

Let `g(x)=e^f(x)), g(x+1)=xg(x),` then `(g'((2n+1)/(2))g((1)/(2))-g'((1)/(2))g((2n+1)/(2)))/(g((2n+1)/(2))g((1)/(2)))`, where `n in N`, is

A

`2 (1+(1)/(2)+(1)/(3)+….+(1)/(n))`

B

`2(1+(1)/(3)+(1)/(5)+….+(1)/(2n-1))`

C

0

D

none of these

Text Solution

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The correct Answer is:
B
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