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If the pair of straight lines `x ysqrt(3)-x^2=0` is tangent to the circle at `Pa n dQ` from the origin `O` such that the area of the smaller sector formed by `C Pa n dC Q` is `3pis qdotu n i t ,` where `C` is the center of the circle, the `O P` equals `((3sqrt(3)))/2` (b) `3sqrt(3)` (c) 3 (d) `sqrt(3)`

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The correct Answer is:
`therefore OP = 3 sqrt3`
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