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If the normal at the point `p(theta)` to the ellipse `5x^(2)+14y^(2)=70` intersects in again the point `Q (2 theta)`, then show that, `cos theta=(2)/(3)`

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The correct Answer is:
`=> (6 cos theta -7) ( 3 cos theta + 2) = 0 => cos theta = (-2)/(3).`
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