The equation of the circumcircle of an equilateral triangle is `x^2+y^2+2gx+2fy+c=0` and one vertex of the triangle in (1, 1). The equation of the incircle of the triangle is `4(x^2+y^2)=g^2+f^2` `4(x^2+y^2)=8gx+8fy=(1-g)(1+3g)+(1-f)(1+3f)` `4(x^2+y^2)=8gx+8fy=g^2+f^2` `non eoft h e s e`

Options

A. `4 (x ^(2) + y^(2)) =g^(2) + b ^(2)`
B. `4 (x ^(2) + y ^(2)) + 8gx + 8fx=g ^(2) + f ^(2)`
C. `4 (x ^(2) + y ^(2)) - 8 gx - 8fy =g^(2) + f ^(2)`
D. none of these

Answer

D