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The line x - b +lambda y = 0 cuts the pa...

The line `x - b +lambda y = 0` cuts the parabola `y^(2) = 4ax (a gt 0)` at `P(t_(1))` and `Q(t_(2))`. If `b in [2a, 4a]` then range of `t_(1)t_(2)` where `lambda in R` is

A

`[-4, -2]`

B

`(-4, -3]`

C

`[-3,-2]`

D

none of these

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The correct Answer is:
A
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