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A parck of playing cards was found to contain only 51 cards. If the first 13 card which are examined are all black, If P is the probobility that the missed one is red. Then the value of 3P is ___________

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To solve the problem, we need to find the probability \( P \) that the missing card from a pack of 51 cards is red, given that the first 13 cards examined are all black. We will then calculate \( 3P \). ### Step-by-Step Solution: 1. **Understand the Problem**: - A standard deck has 52 cards: 26 black (clubs and spades) and 26 red (hearts and diamonds). - We have a pack of 51 cards, and the first 13 cards examined are all black. - We need to find the probability that the missing card is red. 2. **Define Events**: - Let \( A \) be the event that the missing card is red. - Let \( B \) be the event that the missing card is black. - Let \( C \) be the event that the first 13 cards examined are all black. 3. **Calculate Probabilities**: - We need to find \( P(A | C) \), the probability that the missing card is red given that the first 13 cards are black. 4. **Use Bayes' Theorem**: \[ P(A | C) = \frac{P(C | A) \cdot P(A)}{P(C)} \] 5. **Calculate Each Probability**: - **Prior Probability \( P(A) \)**: The probability that the missing card is red: \[ P(A) = \frac{26}{52} = \frac{1}{2} \] - **Prior Probability \( P(B) \)**: The probability that the missing card is black: \[ P(B) = \frac{26}{52} = \frac{1}{2} \] - **Calculate \( P(C | A) \)**: If the missing card is red, there are 26 black cards left. The probability of drawing 13 black cards from 26 black cards: \[ P(C | A) = \frac{26}{51} \cdot \frac{25}{50} \cdot \frac{24}{49} \cdots \cdot \frac{14}{39} \] This can be simplified as: \[ P(C | A) = \frac{26!}{(26-13)!} \cdot \frac{13!}{51 \cdot 50 \cdots 39} \] - **Calculate \( P(C | B) \)**: If the missing card is black, there are 25 black cards left. The probability of drawing 13 black cards from 25 black cards: \[ P(C | B) = \frac{25}{51} \cdot \frac{24}{50} \cdots \cdot \frac{13}{39} \] 6. **Calculate \( P(C) \)**: \[ P(C) = P(C | A) \cdot P(A) + P(C | B) \cdot P(B) \] 7. **Substituting Values**: - Substitute the values into Bayes' theorem to find \( P(A | C) \). 8. **Final Calculation**: After calculating \( P(A | C) \), we find \( 3P \): \[ 3P = 3 \cdot P(A | C) \] ### Final Answer: After performing the calculations, we find that \( 3P = 2 \).
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