Factorize each of the following expressions by splitting the middle term: `8(a+1)^2+2(a+1)(b+2)-15(b+2)^2`

Explanation

`8(a+1)^2+2(a+1)(b+2)-15(b+2)^2`

=`8(a+1)^2+12(a+1)(b+2)-15(b+2)^2`

=`4(a+1)[2(a+1)+3(b+2)-5(b+2)[2(a+1)+3(b+2)]`

=`[2(a+1)+3(b+2)][4(a+1)-5(b+2)]`

=`[2a+2+3b+6][4a+4-5b-10]`

=`[2a+3b+8][4a-5b-6]`