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A stone is dropped from a height of 100 m and at the same time another stone is thrown vertically upwards with velocity of `40ms^(-1)`. When and where will the two stones meet ? `(g=10ms^(-2))`

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The correct Answer is:
`:.` Distance between these two planes after `1^(1//2)` hours `= 300 sqrt(61) km`
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CPC CAMBRIDGE PUBLICATION-TRIANGLES-Exercise 2.5
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