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A square lead slab of side 50cm and thic...

A square lead slab of side 50cm and thickness 5.0cm is subjected to a shearing force (on its narrow face) of magnitude `9.0xx10^(4)` N. The lower edge is riveted to the floor. How much is the upper edge displaced, if the shear modulus of lead is `5.6xx10^(90)` Pa?

Text Solution

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Here, L=50cm`=50xx10^(-2)m,G=5.6xx10^(9)Pa,F=9.0xx10^(4)N`
Area of the face on which force is apllied a `=50xx10=500sq.cm=0.05m^(2)`
If `Delta`L is the displacement of the upper edge of the slab due to tangential force F apllied, then `G=(Fla)/(DeltaL//L)`or`DeltaL=(FL)/(Ga)=(9xx10^(4)xx50xx10^(-2))/(5.6xx10^(9)xx0.05)`
`G=1.6xx10^(-4)m`
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