A mild steel wire of length 1.0 m and cross-sectional are `0.5 xx 10^(-20)cm^(2)` is streached, well within its elastic limit, horizontally between two pillars. A mass of 100 g is suspended from the mid point of the wire, calculate the depression at the mid point.
`g = 10ms^(-2), Y=2 xx 10^(11)Nm^(-2`.

Options

A. `((Mg)/(YA))^(1//3)`
B. `((Mg)/(lA))^(1//3)`
C. `((Mgl^3)/(YA))^(1//3)`
D. `((Mg)/(2YA))`