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Calculate the rms speed of an ideal diat...

Calculate the rms speed of an ideal diatomic gas having molecular weight 32 gm/mol at `0^@ C`. If the specific heats at constant pressure and volume are respectively 8.3 J `mol^(-1) K^(-1) and 6.34` cal `mol^(-1) K^(-1)` respectively.

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To calculate the root mean square (RMS) speed of an ideal diatomic gas, we can use the formula: \[ v_{rms} = \sqrt{\frac{3RT}{M}} \] where: - \( R \) is the universal gas constant, - \( T \) is the absolute temperature in Kelvin, - \( M \) is the molecular weight in kg/mol. ### Step 1: Convert the molecular weight from grams to kilograms Given the molecular weight \( M = 32 \, \text{g/mol} \), we need to convert it to kg/mol: \[ M = \frac{32 \, \text{g/mol}}{1000} = 0.032 \, \text{kg/mol} \] **Hint**: Remember to convert grams to kilograms by dividing by 1000. ### Step 2: Convert the temperature from Celsius to Kelvin The temperature is given as \( 0^\circ C \). To convert this to Kelvin: \[ T = 0 + 273 = 273 \, \text{K} \] **Hint**: To convert Celsius to Kelvin, add 273.15 (for simplicity, we can use 273). ### Step 3: Use the value of the universal gas constant \( R \) The value of the universal gas constant \( R \) in SI units is: \[ R = 8.314 \, \text{J/(mol K)} \] **Hint**: Ensure you are using the correct units for \( R \) (Joules per mole per Kelvin). ### Step 4: Substitute the values into the RMS speed formula Now we can substitute the values of \( R \), \( T \), and \( M \) into the RMS speed formula: \[ v_{rms} = \sqrt{\frac{3 \times 8.314 \, \text{J/(mol K)} \times 273 \, \text{K}}{0.032 \, \text{kg/mol}}} \] ### Step 5: Calculate the numerator Calculating the numerator: \[ 3 \times 8.314 \times 273 = 6816.342 \, \text{J} \] ### Step 6: Divide by the molecular weight Now divide by the molecular weight: \[ \frac{6816.342}{0.032} = 213,011.31 \, \text{m}^2/\text{s}^2 \] ### Step 7: Take the square root Finally, take the square root to find \( v_{rms} \): \[ v_{rms} = \sqrt{213,011.31} \approx 461.28 \, \text{m/s} \] ### Final Answer The RMS speed of the ideal diatomic gas is approximately: \[ v_{rms} \approx 461.28 \, \text{m/s} \] ---
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Calculate the rms speed of an ideal diatomic gas having molecular weight 32 gm/mol at 0^(@)C if the specific heats at constant pressure and volume are respectively 9.3 J mol^(-1)K^(-1) and 6.34 J mol^(-1)K^(-1) respectively.

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