Three perfect gases at absolute temperature `T_1,T_2, and T_3` are mixed. The masses of molecules are `n_1,n_2 and n_3` respectively. Assuming to loss of energy, the final temperature of the mixture is:

Options

A. `(T_1 + T_2 +T_3)/(3)`
B. `(n_(1)^(2) T_(1) + n_(2)^(2) T_(2) + n_(3)^(2) T_(3))/(n_1 + n_2 + n_3)`
C. `(n_1 T_1 + n_2 T_2 + n_3 T_3)/(n_1 + n_2 + n_3)`
D. `(T_1 + T_2 + T_3)/(n_1 + n_2 + n_3)`

Answer

C