Home
Class 12
PHYSICS
If alpha moles of a monoatomic gas are m...

If `alpha` moles of a monoatomic gas are mixed with `beta` moles of a polyatomic gas and mixture behaves like diatomic gas, then [neglect the vibration mode of freedom]

A

`2 alpha = beta`

B

` alpha = 2beta`

C

`alpha = -3 beta`

D

`3 alpha = - beta`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of mixing `alpha` moles of a monoatomic gas with `beta` moles of a polyatomic gas such that the mixture behaves like a diatomic gas, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Degrees of Freedom**: - For a monoatomic gas, the degree of freedom (F) is 3. - For a diatomic gas, F is 5. - For a polyatomic gas, F is 6 (neglecting vibrational modes). 2. **Use the Formula for Specific Heat Capacity**: - The specific heat capacity at constant volume (C_V) for a gas can be expressed as: \[ C_V = \frac{F}{2} R \] - Where R is the universal gas constant. 3. **Calculate Specific Heat Capacities**: - For the monoatomic gas (C1): \[ C_1 = \frac{3}{2} R \] - For the polyatomic gas (C2): \[ C_2 = \frac{6}{2} R = 3R \] 4. **Calculate the Specific Heat Capacity of the Mixture**: - The specific heat capacity of the mixture (C_mixture) behaves like a diatomic gas: \[ C_{mixture} = \frac{5}{2} R \] 5. **Set Up the Equation for the Mixture**: - The specific heat capacity of the mixture can also be expressed as: \[ C_{mixture} = \frac{n_1 C_1 + n_2 C_2}{n_1 + n_2} \] - Substituting the values: \[ \frac{C_{mixture}}{R} = \frac{\alpha \cdot \frac{3}{2} + \beta \cdot 3}{\alpha + \beta} \] 6. **Equate the Two Expressions for C_mixture**: - Setting the two expressions for C_mixture equal: \[ \frac{5}{2} = \frac{\alpha \cdot \frac{3}{2} + \beta \cdot 3}{\alpha + \beta} \] 7. **Cross Multiply to Eliminate the Denominator**: - Cross-multiplying gives: \[ 5(\alpha + \beta) = 3\alpha + 6\beta \] 8. **Rearranging the Equation**: - Expanding and rearranging: \[ 5\alpha + 5\beta = 3\alpha + 6\beta \] \[ 5\alpha - 3\alpha = 6\beta - 5\beta \] \[ 2\alpha = \beta \] ### Final Relation: The final relation between the moles of the gases is: \[ \beta = 2\alpha \]
Promotional Banner

Topper's Solved these Questions

  • KINETIC THEORY

    AAKASH INSTITUTE|Exercise EXERCISE (ASSIGNMENT) SECTION - C Previous Years Questions|21 Videos
  • KINETIC THEORY

    AAKASH INSTITUTE|Exercise EXERCISE (ASSIGNMENT) SECTION - D Assertion - Reason Type Questions|10 Videos
  • KINETIC THEORY

    AAKASH INSTITUTE|Exercise EXERCISE (ASSIGNMENT) SECTION - A Objective Type Questions|30 Videos
  • GRAVITATION

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION - D (ASSERTION-REASON TYPE QUESTIONS)|16 Videos
  • LAWS OF MOTION

    AAKASH INSTITUTE|Exercise Assignment (SECTION-D) (Assertion-Reason Type Questions)|15 Videos

Similar Questions

Explore conceptually related problems

2 moles of monoatomic gas are mixed with "1" mole of a diatomic gas.Then "y" for the mixture is:

N moles of a polyatomic gas (f = 6) must be mixed with two moles of a monoatomic gas so that the mixture behaves as a diatomic gas. The value of N is :

When 1 mole of a monatomic gas is mixed with 3 moles of a diatomic gas, the value of adiabatic exponent g for the mixture is :-

When 1 mole of a monatomic gas is mixed with 3 moles of a diatomic gas, the value of adiabatic exponent gamma for the mixture is

When one mole of monoatomic gas is mixed with one mole of triatomic gas, then the equivalent value of gamma for the mixture will be (vibration mode neglected)

When one mole of monatomic gas is mixed with one mole of a diatomic gas, the equivalent value of gamma for the mixture will be (vibration mode neglected)

Two moles of a monatomic gas is mixed with three moles of a diatomic gas. The molar specific heat of the mixture at constant volume is

One mole of a monatomic gas is mixed with 3 moles of a diatomic gas. What is the molar specific heat of the mixture at constant volume?

The ratio of the number of moles of a monoatomic to a polyatomic gas in a mixture of the two, behaving as an diatomic gas is : (vibrational modes of freedom is to be ignored)

If one mole of a monoatomic gas (gamma=5/3) is mixed with one mole of a diatomic gas (gamma=7/5) the value of gamma for the mixture will be

AAKASH INSTITUTE-KINETIC THEORY-EXERCISE (ASSIGNMENT) SECTION - B Objective Type Questions
  1. A container contains 32 g of O2 at a temperature T. The pressure of th...

    Text Solution

    |

  2. An ideal gas is expanding such that PT^2=constant. The coefficient of ...

    Text Solution

    |

  3. 50 cal of heat is required to raise the temperature of 1 mole of an id...

    Text Solution

    |

  4. Pressure versus temperature graph of an ideal gas is shown in figure. ...

    Text Solution

    |

  5. The energy (in eV) possessed by a neon atom at 27^@ C is

    Text Solution

    |

  6. If heat energy is given to an ideal gas at constant pressure, then se...

    Text Solution

    |

  7. If hydrogen gas is heated to a very high temperature, then the fractio...

    Text Solution

    |

  8. The temperature (T) of one mole of an ideal gas varies with its volume...

    Text Solution

    |

  9. Nitrogen gas is filled in an isolated container. If alpha fraction of ...

    Text Solution

    |

  10. An ideal has undergoes a polytropic given by equation PV^(n) = constan...

    Text Solution

    |

  11. If alpha moles of a monoatomic gas are mixed with beta moles of a poly...

    Text Solution

    |

  12. If different ideal gases are at the same temperature, pressure and hav...

    Text Solution

    |

  13. The internal energy of 10 g of nitrogen at N. T. P. is about

    Text Solution

    |

  14. The mean free path of a molecule of He gas is alpha. Its mean free pat...

    Text Solution

    |

  15. According to C.E. van der Waal, the interatomic potential varies with ...

    Text Solution

    |

  16. The value of critical temperature in terms of van der Waals' constants...

    Text Solution

    |

  17. To find out degree of freedom, the correct expression is:

    Text Solution

    |

  18. Nitrogen gas N2 of mass 28 g is kept in a vessel at pressure of 10 atm...

    Text Solution

    |

  19. A diatomic gas of molecular mass 40 g/mol is filled in rigid container...

    Text Solution

    |

  20. The ratio of average translatory kinetic energy of He has molecules to...

    Text Solution

    |