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The area of the region bounded by the cu...

The area of the region bounded by the curve `y = "sin" x` between the ordinates `x=0`, `x=pi/2` and the `X-"axis"` is

A

`2" sq units"`

B

`4" sq units"`

C

`3" sq units"`

D

`1" sq unit"`

Text Solution

Verified by Experts

The correct Answer is:
D
Area of the bounded by the curve `t=sinx` between the ordinates `x=0,x=pi/2` and the X-axis is

`A=int_(0)^(pi//2)sinxdx`
`=-[cos]_(0)^(pi//2)=-[cos.pi/2-cos0]`
`=-[0-1]=1 " sq unit"`
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NCERT EXEMPLAR-APPLICATION OF INTEGRALS-Application Of Integrals
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