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Show that the function f(x)=|sinx+cosx| ...

Show that the function `f(x)=|sinx+cosx|` is continuous at `x=pi` .

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The correct Answer is:
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We have, `f(x) = |sinx + cosx|` at `x = pi`
Let `g(x) = sinx + cos x`
and ` h(x) = |x|`
` :. hog(x) = h[h(x)]`
`= h (sinx + cosx)`
`= |sinx + cos x|`
Since, `g(x) = sinx + cosx` is a continuous function as it is forming with addition of two continous functions `sinx` and `cosx`.
Also, ` h(x) = |x|` is also a continous function. Since, we know that composite function of two continuous functions is also a continuous function.
Hence, `f(x) = |sinx + cos x|` is a continuous function everywhere.
So, `f(x)` is continuous at `x = pi`.
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