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if f(x)=x^2sin(1/x) , x!=0 then the val...

if `f(x)=x^2sin(1/x) , x!=0` then the value of the function `f` at `x=0` so that the function is continuous at `x=0`

A

0

B

-1

C

1

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
A

`:. f(x) = x^(2)sin(1/x)`, where `x ne 0`
Hence, value of the function f at x = 0, so that it is continuous at `x = 0` is 0.
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