A stream of electrons from a heated filament was passed between two charged plates kept at a potential difference V esu. If c and m are charge and mass of an electron repectively, then the value of `h//lambda` (where `lambda` is wavelength associated with electron wave) is given by :

Options

A. meV
B. 2meV
C. `sqrt(meV)`
D. `sqrt(2meV)`

Answer

D

Explanation

Kinetic energy of electron=charge`xx`potential
`(1)/(2)mv^(2)=eV`
`mv=sqrt(2meV)` ltbr de Broglie wavelength of electron can be calculate as,
`lamda=(h)/(sqrt(2meV))`
`therefore(h)/(lamda)=sqrt(2meV)`.