The vapour of phosphine gas at `27^(@)C` and 3 bar pressure has density:

Options

A. `4.09 g mL^(-1)`
B. `4.14 g L^(-1)`
C. `2.04 kg L^(-1)`
D. `2.04 g L^(-1)`

Answer

B

Explanation

`d = (Pm)/(RT) = (3 xx 34)/(0.0821 xx 300) = 4.14 g L^(-1)`