The molecular weights of two ideal gases A and B are respectively 100 and 200. One gram of A occupies V litre of volume at STP. What is the volume (in litre) occupied by one gram of B at STP ?

Options

A. `(V)/(2)`
B. `V`
C. `V^(2)`
D. `2V`

Answer

A

Explanation

Under identical conditions of temperature and pressure:
`(V_(A))/(V_(B)) = (n_(A))/(n_(B))`
`(V)/(V_(B)) = (1//100)/(1//200)`
`V_(B) = (V)/(2)`