A bubble of volume `V_(1)` is at the bottom of a pond at `15^(@)C` and 1.5 atm pressure. When it comes at the surface, it observes a pressure of 1 atm at `25^(@)C` and has volume `V_(2)`, give `((V_(2))/(V_(1)))`:

Options

A. `15.5`
B. `0.155`
C. `155.0`
D. `1.55`

Answer

D

Explanation

`(P_(1)V_(1))/(T_(1)) = (P_(2) V_(2))/(T_(2))`
`(V_(2))/(V_(1)) = (P_(1) T_(2))/(P_(2) T_(1))`
`= (1.5 xx 288)/(1 xx 298) = 1.5`