If the most probable velocity of methane at a certain temperature is `400 ms^(-1)`, the kinetic energy of one mole of methane at the same temperature in J is:

Options

A. 1024
B. 2048
C. 3072
D. 1920

Answer

D

Explanation

`v_(rms) = (sqrt3)/(sqrt2) xx v_(mp)`
`sqrt((2E)/(m)) = (sqrt3)/(sqrt2) xx 400`
`sqrt((2E)/(16 xx 10^(-3))) = (sqrt3)/(sqrt2) xx 400`
On solving:
`E = 1920 J mol^(-1)`