The diffusion coefficient of an ideal gas is proportional to its mean free path and mean speed. The absolute temperature of an ideal gas is increased 4 times and its pressure is increased 2 times.As a result, the diffusion coefficient of this gas increases `x` times. The value of `x` is........

Answer

4

Explanation

Diffusion coefficient `prop` Mean free path `xx` Average speed
`prop lamda xx v_(av)`
`prop (kT)/(sqrt2 pi sigma^(2)P) xx sqrt((8RT)/(pi m))`
`prop (T^(3//2))/(P)`
`(("Diffusion coefficient")_("final"))/(("Diffusion coefficient")_("initial")) = ((4)^(3//2))/(2) = 4`