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When an electron in an excited state of Mo atoms falls from L to K-shell , an X-ray is emitted. These X-rays are diffracted at angle of `7.75^(@)` by planes with a separation of `2.94 Ã…`. What is the difference in energy between k-shell and L-shell in Mo, assuming of first order diffraction ? ( `sin 7.75^(@)=0.1349`)

Text Solution

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According to Bragg's equation
`nlambda=2dsin theta`
`1xxlambda=2xx2.64 sin 7.75^(@)=2xx2.64xx0.1349`
`lambda=0.712 Ã…`
Energy difference between K and L-shell of Mo
`=(hc)/(lambda)=(6.626xx10^(-34)xx3xx10^(8))/(0.712xx10^(-10))=2.791xx10^(-15) J`
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