Home
Class 11
CHEMISTRY
An element crystallizes in fcc lattice h...

An element crystallizes in fcc lattice having edge length `400 pm` Calculate the maximum diameter of an atom which can be place in interstitial site without distorting the structure.

Text Solution

Verified by Experts

In fcc unit cell , we can use
`asqrt(2)=4r`
`r=(asqrt(2))/(4)=(400xxsqrt(2))/(4)=141.4` pm
For octahedral void,
`2(r+R)=a`
`2R=a-2r`
`2R=a-2r=400-2xx141.4=177.16` pm
Diameter of greatest sphere =117.16 pm
Promotional Banner

Topper's Solved these Questions

  • STATES OF MATTER (SOLID STATE)

    OP TANDON|Exercise Illustrations of Objective Questions|35 Videos
  • STATES OF MATTER (SOLID STATE)

    OP TANDON|Exercise Practice Problems|20 Videos
  • STATES OF MATTER (GASES AND LIQUIDS)

    OP TANDON|Exercise Self Assess,ent|28 Videos
  • THE COLLOIDAL STATE

    OP TANDON|Exercise Self Assessment|21 Videos

Similar Questions

Explore conceptually related problems

An element crystallises in f.c.c. lattice having edge length 400 p m . Calculate the maximum diameter, which can be placed in interstitial sites without disturbing the structure.

An element crystallises in fee lattice having edge length 350 Maximum raduis of the atoms which can be placed in the internal site without distoring the structure is

A metal crystallizes in fcc arrangement with edge length equal to 400 nm. Calculate maximum possible radius of the atom which can fit in the voids without disturbing the crystal structure?

In face - centred cubic (fcc) crystal lattice, edge length is 400 pm. Find the diameter of the greatest sphere which can be fitted into the interstital void without distortion of the lattice.

An element crystallises in a f.c.c. lattice with edge length of 400 pm. Calculate the density if 200 g of this element contain 2.5xx10^(24) atoms.

A metal crystallizes in fcc lattice and edge of the unit cell is 620 pm. The radius of metal atoms is