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If NaCl is doped with 10^(-3) mol% of Sr...

If `NaCl` is doped with `10^(-3)` mol% of `SrCl_(2)`, what is the concentration of cation vacancies?

Text Solution

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`{:(Na^(+),Cl^(-),Na^(+),Cl^(-)),(Cl^(-),,Cl^(-), Na^(+)),(Sr^(2+),Cl^(-),Na^(+),Cl^(-)),(Cl^(-),Na^(+),Cl^(-),Na^(+)):}`
Number of cationic vacancies per mol
`=(10^(-3)xx6.023xx10^(23))/(100)=6.023xx10^(18)` vacancies per mol
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