An element crystallizes into a structure which may be describes by a cubic type of unit cell having one atom on each corner of the cube and two atoms on one of its diagonals. If the volume of this unit cell is `24xx10^(-24)cm^(3)` and density of element is `7.2g cm^(-3)` . Calculate the number of atoms present in `200g` of element.

Explanation

Number of atoms in a unit cell (Z)=1+2=3
`Z=(l^(3)xxrhoxxN)/(M)`
`M=(l^(3)xxrhoxxN)/(Z)`
`=(24xx10^(-24)xx7.2xx6.023xx10^(23))/(3)=34.69`
Number of atoms `=("Mass")/("Molar mass")xx6.023xx10^(24)`
`(200)/(34.69)xx6.023xx10^(23)=3.47xx10^(24)`