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Sodium metal exits in bcc unit cell .The...

Sodium metal exits in bcc unit cell .The distance between nearest sodium atoms is 0.368 nm. The edge length of the unit cell is:

A

0.368 nm

B

0.184nm

C

0.575 nm

D

0.425 nm

Text Solution

Verified by Experts

The correct Answer is:
D
In bcc unit cell , `asqrt(3)=4r`
`a=(4r)/(sqrt(3))=(2)/(sqrt(3))xx2r`
`=(2)/(sqrt(3))xx0.368=0.425 nm`
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