A solid AB has CsCl-type structure. The ...

A solid `AB` has `CsCl`-type structure. The edge length of the unit cell is `404` pm. Calculate the distance of closest approach between `A^(o+)` and `B^(Θ)` ions.

250 pm

349.9 pm

349.4pm

450 pm

Text Solution

Verified by Experts

The correct Answer is:

Distance of closest approach in bcc unit cell
`=(asqrt(3))/(2)=(404xx1.732)/(2)`
`=349.9` pm

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