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The arrangement of X^(ɵ) ions around A^(...

The arrangement of `X^(ɵ)` ions around `A^(o+)` ion in solid `AX` is given in the figure (not drawn to scale). If the radius of `X^(ɵ)` is `250 pm`, the radius of `A^(o+)` is

A

104 pm

B

125 pm

C

183 pm

D

57 pm

Text Solution

Verified by Experts

The correct Answer is:
A
For octahedral voids : `(r^(+))/(r_(-))=0.414-0.732`
`r^(+)=0.414xxr^(-)=0.414xx250=10.3.5` pm
or `r^(+)=0.732xx250=183` pm
No, suitable information is given therefore 104 pm will be most suitable answer by considering the extact fit ion in the void.
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