Home
Class 11
CHEMISTRY
In an ionic compound XY(2)O(4) oxide ion...

In an ionic compound `XY_(2)O_(4)` oxide ions are arranged in ccp. Cations `X` are present in octahedral voids.Cations `Y` are equally distributed between octahedral voids occupied is

A

`(1)/(4)`

B

`(1)/(2)`

C

`(1)/(6)`

D

`(1)/(8)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • STATES OF MATTER (SOLID STATE)

    OP TANDON|Exercise SELF ASSESSMENT Section II|4 Videos

  • STATES OF MATTER (SOLID STATE)

    OP TANDON|Exercise SELF ASSESSMENT Section III|5 Videos

  • STATES OF MATTER (SOLID STATE)

    OP TANDON|Exercise Linked Comprehension Type Questions|14 Videos

  • STATES OF MATTER (GASES AND LIQUIDS)

    OP TANDON|Exercise Self Assess,ent|28 Videos

  • THE COLLOIDAL STATE

    OP TANDON|Exercise Self Assessment|21 Videos

Similar Questions

Explore conceptually related problems

In a compound XY_(2) O_(4) , oxide ions are arranged in CCP and cations X are present in octahedral voids. Cations Y are equally distributed between octahedral and tetrahedral voids. The fraction of the octahedral voids occupied is :-

In a crystalline solid, having formula AB_(2)O_(4) oxide ions are arranged in cubic close packed lattice while cations A are present in tetrahedral voids and cations B are present in octahedral voids. (a) What percentage of the tetrahedral voids is occupied by A? (b) What percentage of the octahedral voids is occupied by B ?

In an ionic compound, oxide ions have ccp arrangement Cations A are present in one eighth of the tetrahedral voids whilst cations B occupy half of the octahedral voids.the empirical formula of the compound is

In zinc blende structure anions are arranged in ccp and cations are present in the tetrachedral voids and only half the tetrahedral voids are occupied, the coordination numbers of cation and anion are respectively

In a crystallizes solid, anions B are arranged in cubic close packing, cations A are equally distributed between octahedral and tetrahedral voids, what is the formula of the solid?

In zinc blende structure anions are arranged in ccp and cations are present in the tetrachedral voids and only half the tetrahedral voids are occupied, if 'a' is the edge length of the unit cell then for zinc blende structure the distance of closest approach between cation and anion is

In zinc blende structure anions are arranged in ccp and cations are present in the tetrachedral voids and only half the tetrahedral voids are occupied, for this type of structure , radius ratio r/r should be in the range

In a crystalline solid, anions Y are arranged in ccp arrangement. Cations 'X' are equally distributed between tetrahedral and Octahedral voids. If all the octahedral voids are occupied, what is the formula of solid ?

In a crystalline solid, anions B are arranged in ccp structure. Cations A are equally distributed between octahedral and tetrahedral voids if all the octahedral voids are occupied the formula of the ionic solids will be