`SO_(2)` is oxidised to `SO_(4)^(2-)` in acid medium. Calculate equivalent mass of `SO_(2)`.
Text Solution
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`overset(+4) (SO_(2))(g) +2H_(2)O to overset(+2+6-8)(H_(2)SO_(4))+2H^(+)+2e^(-)` Change in oxidation number of sulphur =6-4=2 Equivalent mass of `SO_(2)= ("Molecular mass")/(2)=(64)/(2)=32`
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