250 mL of x M solution and 500 mL of y M...

250 mL of x M solution and 500 mL of y M solution of a solute A are mixed and diluted to 2 litre to produce a final concentration of 1.6 M.

Text Solution

Verified by Experts

We Know that,
`M_(1)V_(1)+M_(2)V_(2)=M_(R )(V_(1)+V_(2))`
`x xx 250+yxx500=1.6(2000)`
`x+2y=1.6xx8`
x+2y = 12.8
`(x)/(y)+2=(12.8)/(y)`
`(5)/(4)+2=(12.8)/(y)`
`(13)/(4)=(12.8)/(y)`
`y=(12.8xx4)/(13)=3.94`
Similary, `" " ` x=4.92

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250 mL of XM solution and 500 mL of yM solution of a solute are mixed and diluted to 2 L to produce a solution having concentration 1.6 M. If x : y = 5:4, then x + y is

` 8.06 `

`8.86`

`9.8 `

`12.6`

200 mL of water is added to 500 mL of 0.2 M solution. What is the molarity of the diluted solution ?

0.5010 M

0.2897 M

0.7093 M

0.1428 M

When 10 mL of 10 M solution of H_(2)SO_(4) and 100 mL of 1 M solution of NaOH are mixed, the resulting solution will be :

acidic

neutral

alkaline

Cannot be predicted