50 mL of an aqueous solution of `H_(2)O_(2)` was treated with an excess of KI solution and dilute `H_(2)SO_(4)`. The liberated iodine required 20 mL 0.1 N `Na_(2)S_(2)O_(3)` solution for complete interaction. Calculate the concentration of `H_(2)O_(2)` in `g//L`.
Text Solution
Verified by Experts
`H_(2)O_(2)+2KI+H_(2)SO_(4) to K_(2)SO_(4)+2H_(2)O+I_(2)` `2Na_(2)S_(2)O_(3)+I_(2) to Na_(2)S_(4)O_(6)+2NaI` Eq. mass `H_(2)O_(2)=(34)/(2)=17` 20 mL 0.1 N `Na_(2)S_(2)O_(3)=20 mL 0.1 N I_(2)` solution `-=20 mL 0.1 N H_(2)O_(2)` solution Amount of `H_(2)O_(2)` in 50 mL aq. solution `=(0.1xx17)/(1000)xx20=0.034g` Concentration in `g//L =(0.034)/(50)xx1000=0.68`
Topper's Solved these Questions
VOLUMETRIC ANALYSIS
OP TANDON|Exercise Example 1|2 Videos
VOLUMETRIC ANALYSIS
OP TANDON|Exercise Example 2|2 Videos
VOLUMETRIC ANALYSIS
OP TANDON|Exercise Example 6|3 Videos
THE COLLOIDAL STATE
OP TANDON|Exercise Self Assessment|21 Videos
Similar Questions
Explore conceptually related problems
When 100 mL of an aqueous of H_(2)O_(2) is titrated with an excess of KI solution in dilute H_(2)O_(2) , the liberated I_(2) required 50 mL of 0.1 M Na_(2) S_(2)O_(3) solution for complete reaction. Calculate the percentage strength and volume strength of H_(2)O_(2) solution.
When 100 " mL of " an aqueous solution of H_2O_2 is titrated with an excess of KI solution in dilute H_2SO_4 , the liberated I_2 required 50 " mL of " 0.1 M Na_2S_2O_3 solution for complete reaction. Calculate the percentage strength and volume strength of H_2O_2 solution.
