In the reaction,
`FeS_(2)+KMnO_(4)+H^(+) to Fe^(3+)+SO_(2)+Mn^(2+)+H_(2)O`
the equivalent mass of `FeS_(2)` would be equal to :

Options

A. molar mass
B. `("molar mass")/(10)`
C. `("molar mass")/(11)`
D. `("molar mass")/(13)`

Answer

C

Explanation

`Fe^(2+) to Fe^(3+) + e^(-), S_(2)^(2-) to 2S^(4+)+10e^(-)`
`therefore FeS_(2) to 2S^(4+)+Fe^(3+)+11e^(-)`
Equivalent mass of `FeS_(2) =("Molar mass")/(11)`