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X gm of metal gave Y gm of its oxide, so...

X gm of metal gave Y gm of its oxide, so equivalent mass of metal is :

A

`((X)/(Y-X))xx8`

B

`((Y-X)/(X))xx8`

C

`((Y+X)/(X))xx8`

D

`(X)/(Y)xx8`

Text Solution

Verified by Experts

The correct Answer is:
A
Mass of oxygen in the oxide =(Y-X)
`therefore 8g` oxygen will combine with `(X)/(Y-X)xx8g` metal.
`therefore " " E=((X)/(Y-X))xx8`
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