1 mol `H_(2)SO_(4)` will exactly neutralise :

Options

A. 2 mol of ammonia
B. 1 mol of `Ba(OH)_(2)`
C. 0.5 mol of `Ba(OH)_(2)`
D. 2 mol of KOH

Explanation

To solve the question of how many moles of different substances can be neutralized by 1 mole of sulfuric acid (H₂SO₄), we need to understand the concept of gram equivalents and neutralization reactions.

### Step-by-Step Solution:

1. **Understanding Neutralization**:
Neutralization occurs when an acid reacts with a base to form water and a salt. The number of equivalents of acid must equal the number of equivalents of base for complete neutralization.

2. **Determine the Equivalent Factor of H₂SO₄**:
- H₂SO₄ is a diprotic acid, meaning it can donate 2 protons (H⁺ ions).
- Therefore, 1 mole of H₂SO₄ can provide 2 equivalents of H⁺.
- Thus, 1 mole of H₂SO₄ = 2 equivalents.

3. **Calculate the Equivalent Factors of the Bases**:
- **Ammonia (NH₃)**:
- Ammonia can accept 1 proton (H⁺), so 1 mole of NH₃ = 1 equivalent.
- To neutralize 2 equivalents of H₂SO₄, we need 2 moles of NH₃.
- **B(OH)₂ (Boron hydroxide)**:
- B(OH)₂ can provide 2 OH⁻ ions, so 1 mole of B(OH)₂ = 2 equivalents.
- This can also neutralize 1 mole of H₂SO₄.
- **KOH (Potassium hydroxide)**:
- KOH can provide 1 OH⁻ ion, so 2 moles of KOH = 2 equivalents.
- This can also neutralize 1 mole of H₂SO₄.

4. **Summarizing the Results**:
- 1 mole of H₂SO₄ can neutralize:
- 2 moles of NH₃ (2 equivalents)
- 1 mole of B(OH)₂ (2 equivalents)
- 2 moles of KOH (2 equivalents)

5. **Conclusion**:
- The substances that can be neutralized by 1 mole of H₂SO₄ are:
- 2 moles of NH₃
- 1 mole of B(OH)₂
- 2 moles of KOH

### Final Answer:
1 mole of H₂SO₄ will exactly neutralize:
- 2 moles of NH₃
- 1 mole of B(OH)₂
- 2 moles of KOH