Home
Class 11
CHEMISTRY
A 100 mL solution of 0.1 N HCl was titra...

A 100 mL solution of 0.1 N HCl was titrated with 0.2 N NaOH solution. The titration was discontinued after adding 30 mL of NaOH solution. The titration was completed by adding 0.25 N KOH solution. The volume of KOH required for completing the titration is :

A

70 mL

B

32 mL

C

35 mL

D

16 mL

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • VOLUMETRIC ANALYSIS

    OP TANDON|Exercise Objective Question (Level-B)|38 Videos
  • VOLUMETRIC ANALYSIS

    OP TANDON|Exercise Assertion-Reason Type Questions|10 Videos
  • VOLUMETRIC ANALYSIS

    OP TANDON|Exercise Practice Problems|76 Videos
  • THE COLLOIDAL STATE

    OP TANDON|Exercise Self Assessment|21 Videos

Similar Questions

Explore conceptually related problems

Objective question (single correct answer). i. H_(3) PO_(4) is a tribasic acid and one of its salt is NaH_(2) PO_(4) . What volume of 1M NaOH solution should be added to 12 g of NaH_(2) PO_(4) to convert in into Na_(3) PO_(4) ? a. 100 mL b. 2 mol of Ca (OH)_(2) c. Both d. None iii. The normality of a mixture obtained mixing 100 mL of 0.2 m H_(2) SO_(4) with 100 mL of 0.2 M NaOH is: a. 0.05 N b. 0.1 N c. 0.15 N d. 0.2 N iv 100 mL solution of 0.1 N HCl was titrated with 0.2 N NaOH solutions. The titration was discontinued after adding 30 mL of NaOH solution. The reamining titration was completed by adding 0.25 N KOH solution. The volume of KOH required from completing the titration is: a. 70 mL b. 35 mL c. 32 mL d. 16 mL

50 cm^(3) of 0.2 N HCl is titrated against 0.1 N NaOH solution. The titration is discontinued after adding 50 cm^(3) of NaOH solution. The remaining titration is completed by adding 0.5 N KOH solution. What is the volume of KOH required for completing the titration ?

OP TANDON-VOLUMETRIC ANALYSIS-Objective Question (Level-A)
  1. The molar concentration of the chloride ion in the solution obtained b...

    Text Solution

    |

  2. The normality of 0.3 M phosphorous acid (H(3)PO(3)) is :

    Text Solution

    |

  3. A 100 mL solution of 0.1 N HCl was titrated with 0.2 N NaOH solution. ...

    Text Solution

    |

  4. An aqueous solution of 6.3 g of oxalic acid dihydrate is made up to 25...

    Text Solution

    |

  5. In order to prepare one litre nomal solution of KMnO(4), how many gram...

    Text Solution

    |

  6. 3 g of an oxide of a metal is converted to chloride completely and it ...

    Text Solution

    |

  7. Phosphoric acid H(3)PO(4) can not be neutralised to :

    Text Solution

    |

  8. a' g KHC(2)O(4) required to reduce 100 mL of 0.02 M KMnO(4) in acid me...

    Text Solution

    |

  9. Which of the following statements is not true about H(3)PO(2) ?

    Text Solution

    |

  10. Mixture of 1 mole BaF(2) and 2 mole H(2)SO(4) can not be neutralised b...

    Text Solution

    |

  11. 28 NO(3)^(-) + 3As(2)S(3) + 4H(2)O to 6AsO(4)^(3-)+28 NO+ 9SO(4)^(2-) ...

    Text Solution

    |

  12. The number of moles of KMnO(4) that will need to react completely with...

    Text Solution

    |

  13. The number of moles of KMnO(4) that will be needed to react with one m...

    Text Solution

    |

  14. The equivalent weight of KIO(3) in the reaction, 2Cr(OH)(3)+OH^(-)+K...

    Text Solution

    |

  15. In the reaction, I(2)+2S(2)O(3)^(2-) to 2I^(-)+S(4)O(6)^(2-) equi...

    Text Solution

    |

  16. The volume of a concentrated H(2)SO(4), mixed with 0.5 N KOH to prepar...

    Text Solution

    |

  17. For the decolorisation of 1 mole of KMnO(4), the number of moles of H(...

    Text Solution

    |

  18. The product of oxidation of I^(-) " with " MnO(4)^(-) in alkaline medi...

    Text Solution

    |

  19. Volume of 0.1 M K(2)Cr(2)O(7) required to oxidise 35 mL of 0.5 M FeSO(...

    Text Solution

    |

  20. A commercial sample of H(2)O(2) is labelled 10 volume. Its percentage ...

    Text Solution

    |