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50 mL of 10 N H(2)SO(4), 25 mL of 12 N H...

50 mL of `10 N H_(2)SO_(4)`, 25 mL of 12 N HCl and 40 mL of 5 N `HNO_(3)` are mixed and the volume of the mixture is made 1000 mL by adding water. The normality of the resulting solution will be :

A

1 N

B

2 N

C

3 N

D

4 N

Text Solution

Verified by Experts

The correct Answer is:
A

`N_(1)V_(1)+N_(2)V_(2)+N_(3)V_(3)=N_(R )xxV_(R )`
`10xx50+12xx25+5xx40=N_(R )=xx1000`
`500+300+200=N_(R )=1000`
`N_(R )=1` (Resulatnt normality)
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