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To neutralise completely 20 mL of 0.1 M ...

To neutralise completely 20 mL of 0.1 M aqueous solution of phosphorus acid `(H_(3)PO_(3))`, the volume of 0.1 M aqueous KOH solution required is :

A

10 mL

B

20 mL

C

40 mL

D

60 mL

Text Solution

Verified by Experts

The correct Answer is:
C
`H_(3)PO_(3)+2KOH to K_(2)HPO_(3)+2H_(2)O`
`(M_(1)V_(1))/(n_(1))=(M_(2)V_(2))/(n_(2))`
`(0.1xx20)/(1)=(0.1xx V_(2))/(2)`
`V_(2)= 40 mL`
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