Home
Class 11
PHYSICS
The blades of a windmill sweep out a cir...

The blades of a windmill sweep out a circle of area A. If the wind flows at a velocity v perpendicular to the circle, then the mass of the air of density `rho` passing through it in time t is

A

`Avrhot`

B

`2Avrhot`

C

`Av^2rhot`

D

`1/2Avrhot`

Text Solution

Verified by Experts

The correct Answer is:
A

Volume of wind flowing per second = Av
Mass of wind flowing per second = `Avrho`
Mass of air passing in time t s = `Avrhot`
Promotional Banner

Topper's Solved these Questions

  • WORK , ENERGY AND POWER

    NCERT FINGERTIPS|Exercise Work Done By A Variable Force|3 Videos
  • WORK , ENERGY AND POWER

    NCERT FINGERTIPS|Exercise The Work Energy Theorem For A Variable Force|3 Videos
  • WORK , ENERGY AND POWER

    NCERT FINGERTIPS|Exercise Work|14 Videos
  • WAVES

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

The blades of a windmill sweep out a circle of area A. (a) If the wind flows at a velocity v perpendicular to the circle, what is the mass of the air passing through in time t? (b) What is the kinetic energy of the air? (c) Assume that the windmill converts 25% of the wind's energy into electrical energy, and that A=30m^2 , v=36kmh^-1 and the density of air is 1.2kgm^-3 , what is the electrical power produced?

The blades of a windmill sweep out a circle of area A. (a) If the wind flows at a velocity upsilon perpendicular to the circle, what is the mass of air passing through it in time t? (b) What is K.E. of the air ? (c) Assume that the wind mill converts 25% of the wind's energy into electrical energy , and that A=30m^(2), upsilon=36km//h and the density of air is 1.2kg//m^(3) . What is electrical power produced ?

The blades of a wind mill sweep out a circle of area A. If wind flows with velocity v perpendicular to blades of wind mill and its density is p , then the mechanical power received by wind mill is

The power P delivered by a windmill whose blades sweep in a circle of diameter D by a wind of speed v is proportional to the square of the diameter and the cube of the wind speed. Show that this dependence on diameter and wind speed exist when 100% energy transfer takes place. Also show that P=pi/8 rhoD^(2)v^(3) Where is rho the density of air.

A copper rod is bent inot a semi-circle of radius a and at ends straight parts are bent along diameter of the semi-circle and are passed through fixed, smooth and conducting ring O and O' as shown in figure. A capacitor having capacitance C is connected to the rings. The system is located in a uniform magnetic field of induction B such that axis of rotation O O' is perpendicular to the field direction. At initial moment of time (t = 0) , plane of semi-circle was normal to the field direction and the semi-circle is set in rotation with constant angular velocity omega . Neglect the resistance and inductance of the circuit. The current flowing through the circuit as function of time is

The air of density rho and moving with a velocity v strikes perpendicular the inclined surface of area A and of a wedge kept on a horizontal surface. The mass of the wedge is m . Assuming the collisions to be perfectly inelastic, the minimum value of the coefficient of friction between the wedge and the ground so that the wedge does not move is (Assume mass of particles of air is negligible)

The flow speeds of air on the lower and upper surfaces of the wing ofan aeroplane are v and sqrt2v respectively. A is the area of the wing and rho is the density of th e surrounding air. What is the force of the dynamic lift on the wing ?

The surface density (mass/area) of a circular disc of radius a depends on the distance from the centre as rho(r)=A+Br. Find its mment of inertia about the line perpendicular to the plane of the disc through its centre.