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Two springs of spring constants 1000 N m...

Two springs of spring constants `1000 N m^(-1)` and `2000 N m^(-1)` are stretched with same force. They will have potential energy in the ratio of

A

`2:1`

B

`2^2 :1^2`

C

`1:2`

D

`1^2 :2^2`

Text Solution

Verified by Experts

The correct Answer is:
A
Potential energy
`U=1/2kx^2=1/2k(F/k)^2=F^2/(2k)`
`U_1xxk_1=U_2xxk_2 " " or " " U_1/U_2=k_2/k_1 =2000/1000=2/1`
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